The mole fraction of NaCl in a mixture : 0.195
Further explanation
The mole fraction shows the mole ratio of the compound to the moles of the mixture/solution
Can be formulated :
[tex]\tt x_1=\dfrac{n_1}{n_{tot}}[/tex]
n tot = n₁+n₂+....nₙ
a mixture of 0.564 g NaCl,
1.52 g KCI, and 0.857 g LiCl
- mol NaCl (MW=58.44 g/mol)
[tex]\tt \dfrac{0.564}{58,44 g/mol}=0.0097[/tex]
[tex]\tt \dfrac{1.52}{74.55}=0.02[/tex]
mol LiCl(MW=42,394 g/mol)
[tex]\tt \dfrac{0.857}{42,394 g/mol}=0.02[/tex]
n total =
[tex]\tt 0.0097+0.02+0.02=0.0497[/tex]
the mole fraction of NaCl :
[tex]\tt \dfrac{0.0097}{0.0497}=0.195[/tex]
