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part 1: What is the final volume in milliliters when 0.730 L of a 44.8 % (m/v) solution is diluted to 23.3 % (m/v)?
part 2:A 739 mL NaCl solution is diluted to a volume of 1.50 L and a concentration of 2.00 M . What was the initial concentration?

Respuesta :

ardni313

part 1 : the final volume : 1.404 L

part 2 : the initial concentration : 4.06 M

Further explanation

Dilution is the process of adding a solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

part 1 :

M₁=44.8%

V₁=0.73 L

M₂=23.3%

[tex]\tt V_2=\dfrac{M_1.V_1}{M_2}\\\\V_2=\dfrac{44.8\times 0.73}{23.3}\\\\V_2=1.404~L[/tex]

part 2 :

V₁=739 ml=0.739 L

V₂=1.5 L

M₂=2

[tex]\tt M_1=\dfrac{M_2.V_2}{V_1}\\\\M_1=\dfrac{2\times 1.5}{0.739}\\\\M_1=4.06[/tex]