Answer:
[tex]x=19[/tex]
Step-by-step explanation:
[tex]2^2^0-2^1^9=2^x[/tex]
[tex]2^x=524288[/tex]
[tex]log(2^x)=log(524288)[/tex]
[tex]x=\frac{log(524288)}{log(2)}[/tex]
