Answer:
x≥3/4 and x≥1/2
Step-by-step explanation:
Given the inequality
[tex]\left(4x-3\right)\left(2x-1\right)\ge0[/tex]
We are to find the solution set of the inequality
[tex]\left(4x-3\right)\ge0 \ and \ \left(2x-1\right)\ge0\\4x - 3\ge0 \\4x \ge 3\\x\ge 3/4\\\\Also;\\2x - 1 \ge0\\2x \ge1\\x \ge 1/2[/tex]
The solution sets are x≥3/4 and x≥1/2
