Answer:
[tex] x=3\sqrt 5\\[/tex]
[tex]y = \sqrt {126}[/tex]
Step-by-step explanation:
By geometric mean property:
[tex]x = \sqrt{9 \times 5} = \sqrt{45} = 3 \sqrt{5} \\ \\ by \: pythagoras \: theorem \\ \\ {y}^{2} = {9}^{2} + {x}^{2} \\ \\ {y}^{2} = {9}^{2} + {(3 \sqrt{5}) }^{2} \\ \\ {y}^{2} = 81 + 45 \\ \\ {y}^{2} = 126 \\ \\ y = \sqrt{126} [/tex]
