Answer:
[tex] \tan(51°) = \frac{10}{x} \\x = \frac{10}{ \tan(51°) } \\ x = \frac{10}{1.235} \\ \boxed{ x = 8.1}[/tex]
★ Value of x is 8.1.
[tex] \sin(51°)= \frac{10}{H} \\ h = \frac{10}{ \sin(51°) } \\ H= \frac{10}{0.777} \\ \boxed{H= 12.8676}[/tex]
★ Value of H is 12.8676.
Remember:
- tan∅=Perpendicular/Base
- sin∅=Perpendicular/Hypotenuse
