Answer:
The vertex form parabola y = 2( x+4)² -37
Step-by-step explanation:
Step(i):-
Given parabola equation j(x) = 2x² + 8x -5
Let y = 2x² + 8x -5
⇒ y = 2(x² + 2(4x)+(4)²-(4)²) -5
By using (a + b)² = a² +2ab +b²
y = 2(x+4)²- 32 -5
y = 2 ( x-(-4))² -37
Step(ii):-
The vertex form parabola y = a( x-h)² +k
The vertex form parabola y = 2(x+4)² -37
