Respuesta :

Answer:

The numbers can be either -8,-7,-6, or 6, 7, 8.

n(n−1)(n+1)=16(n−1+n+n+1)  

⟹n(n2−1)=16×3n  

⟹n(n2−1)n=48nn  

⟹(n2−1)−48=48−48  

⟹n2−49=0  

⟶(n−7)(n+7)=0  

n  can be  7  or  −7 , so the numbers can be either  −8,−7,−6  

Or

6,7,8

Step-by-step explanation:
6,7,8 is are variable

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