Answer:
Step-by-step explanation:
Let the transmitter be located at (0,0)
The equation for its effective coverage area will be a circle centered at  (0,0)  with a radius of 49.
So....the equation is Â
[tex]x^2 + y^2 = 49^2[/tex]
[tex]x^2 + y^2 = 2401[/tex]
Let the point 67 miles north of the transmitter be (0, 67)
Let the point 63 Â miles east of the transmitter be (63, 0)
The line connecting these (the line of travel) Â will have a slope of
[67 - 0] / [ 0 - 63] Â = Â -67/63
The equation of this line will be: y  = (-67/63)x  + 67
The signal will be received between the points:
(21.681, 43.942) Â and (45.192, 18.938)
The distance between these points  is
[tex]\sqrt{[ ( 45.192 - 21.681)^2 + ( 43.942 - 18.938)^2 ] } = 34.322 miles[/tex] Â Â (1)
The distance  between (0, 63) and (67, 0)
[tex]\sqrt{[ ( 63)^2 + ( 67)^2 ] }=91.97miles[/tex] (2)
So....you will receive the signal using  (1)/ (2)  Â
(34.322 / 91.97) x 100  ≈  37%  of the drive