Answer:
the zeros are f(x= 3) and f(x= -4)
Step-by-step explanation:
x²+x-12
x²+4x-3x-12
x(x+4) -3(x+4)
(x-3) (x+4)
x=3 and x= -4
f(x)= x²+x-12
using x=3;
f(3)= 3²+3-12 = 9+3-12= 12-12=0
using x= -4;
f(-4)= (-4)² + (-4) - 12= 16-4-12= 12-12= 0
the zeros are f(x= 3) and f(x= -4)
