Answer:
The value of f(3) = -2.
Step-by-step explanation:
First of all, let's find f(2).
[tex]f(n+1)=f(n)^{2}-3[/tex]
[tex]f(1+1)=f(1)^{2}-3[/tex]
[tex]f(2)=f(1)^{2}-3=2^{2}-3=1[/tex]
Now, we can find f(3):
[tex]f(2+1)=f(2)^{2}-3[/tex]
[tex]f(3)=f(2)^{2}-3=1^{2}-3=-2[/tex]
Therefore, the value of f(3) = -2.
I hope it helps you!
