Step-by-step explanation:
Given
[tex]f(x) = \frac{x + 5}{x} [/tex]
So
[tex]f(2) = \frac{2 + 5}{2} \\ = \frac{7}{2} [/tex]
Now
[tex] {f}^{ - 1} (x) = \frac{5}{x - 1} [/tex]
So
[tex] {f}^{ - 1} (2) = \frac{5}{2 - 1} \\ = \frac{5}{ 1} \\ = 5[/tex]
Hope it will help :)❤
