Answer:
The diameter of the gold nucleus is 3.0 × 10⁻⁵ nm
Explanation:
The given parameter of the gold atom are;
The diameter of the gold atom = 1/6,000 × The diameter of the atom
The diameter of a gold atom = 0.18 nm
The diameter of the gold nucleus, [tex]d_{Gold -nucleus}[/tex] = 1/6,000 × 0.18 nm = 0.00003 nm
∴ The diameter of the gold nucleus, [tex]d_{Gold -nucleus}[/tex] = 0.00003 nm = 3.0 × 10⁻⁵ nm.
