Answer:
[tex] \huge a)\frac{1}{ {3}^{9}. {6}^{18} }[/tex]
Step-by-step explanation:
to understand this
you need to know about:
tips and formulas:
- [tex] {x}^{ - y} < = > \frac{1}{ {x}^{y} } [/tex]
- [tex]( {x} ^{z} )^{y} < = > {x}^{y \times z} [/tex]
let's solve:
[tex]( {3}^{3} . {6}^{6} {)}^{ - 3} [/tex]
[tex] \frac{1}{( {3}^{3}. {6}^{6} {)}^{3} } [/tex]
[tex] \frac{1}{ {3}^{3 \times 3}. {6}^{6 \times 3} } [/tex]
[tex] \frac{1}{ {3}^{9}. {6}^{18} }[/tex]
