Volume of ammonia gas : 10.67 L
Further explanation
Given
10.0 L of nitrogen gas
16.0 L of hydrogen gas
Required
Volume of ammonia gas
Solution
Reaction
N₂ + 3H₂ ⇒ 2NH₃
From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles
Find limiting reactant :
N₂ : 10 : 1 = 10
H₂ : 16 : 3 = 5.3
H₂ as a limiting reactant
So volume of NH₃ based on H₂
= 2/3 x volume H₂
= 2/3 x 16 L
= 10.67 L
