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A mixture of cyclopropane (C3H6) and oxygen (O2) is sometimes used as a general anesthetic. In a mixture, the partial pressures of cyclopropane and oxygen are 170. torr and 570. torr, respectively. Calculate the ratio of the moles of oxygen to the moles of cyclopropane in the mixture.

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ayfat23

Answer:

0.30

Explanation:

Provided that the volume and pressure remains constant

[(Pressure of cyclopropane)/ (Pressure of Oxygen)] = [(no. Of moles of cyclopropane)/(no. Of moles of Oxygen)]

Pressure of cyclopropane= 170. torr

Pressure of Oxygen= 570. torr

If we substitute the values

[(no. Of moles of cyclopropane)/(no. Of moles of Oxygen)] = 170/570

[(no. Of moles of cyclopropane)/(no. Of moles of Oxygen)] = 0.30

Hence, the ratio of the moles of oxygen to the moles of cyclopropane in the mixture is 0.30

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