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04-11-2016
Mathematics

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find the vertex for quadratic function y=2x^2-20x+10

Respuesta :

04-11-2016

2x^2 - 20x = y - 10
x^2 - ( 20/4 )^2 + ( 20/4 )^2 = y - 10
( x - 5 )^2 = y - 10 - 25
( x - 5 )^2 = y - 35
Vertex = ( 5 , 35 )

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