Answer:
1.94 atm is the pressure at underwater site.
19.4 meters is the depth of the underwater site.
Explanation:
Pressure of the balloon at the dept at which scuba diver is working:
= [tex]P_1=?[/tex]
Volume of the balloon at the dept at which scuba diver is working:
= [tex]V_1=181 L[/tex]
Pressure of the balloon at the surface:
= [tex]P_2=1 atm[/tex]
Volume of the balloon at the dept at which scuba diver is working:
= [tex]V_1=351 L[/tex]
Using Boyle's law:
[tex]P_V_1=P_2V_2[/tex] (at constant temperature)
[tex]P_1=\frac{P_2V_2}{V_1}=\frac{1 atm\times 351 L}{181 L}=1.94 atm[/tex]
1.94 atm is the pressure at underwater site.
Pressure increases by exactly 1.0 atm for every 10 m depth.
Pressure increase for every 1 unit increase in depth= [tex]\frac{1.0}{10}atm/m=0.1 atm/m[/tex]
Depth at which pressure is 1.94 atm = h
[tex]h\times 0.1 atm/m=1.94 atm[/tex]
[tex]h=\frac{1.94 atm}{0.1 atm/m}=19.4 m[/tex]
19.4 meters is the depth of the underwater site.
