1. You have 2 m3 of a mineral ore sample. It has a mass of 1 _ 104 kg. Calculate the density of the ore sample and express your results in g/cm3 with appropriate scientific notation

Respuesta :

The solution to your problem is as follows:

2 m3 is 2e6 cm3 

1e4 kg is 1e7 g 

so 

d = m/V = 1e7/2e6 = 5 g/cm3

Therefore, the density of the ore sample is 5 g/cm3.


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Answer:

Density = 5 g/cm³

Step-by-step explanation:

We have density, ρ is the ratio of mass m and volume, V.

That is  

            [tex]\rho =\frac{m}{V}[/tex]

Mass, m= 1 x 10⁴ kg

Volume, V = 2 m³

Substituting in expression of density,

           [tex]\rho =\frac{m}{V}=\frac{1\times 10^4}{2}=5000kg/m^3\\\\\rho=\frac{5000\times 10^3g}{10^6cm^3}=5g/cm^3[/tex]

Density = 5 g/cm³