Respuesta :
The solution to your problem is as follows:
2 m3 is 2e6 cm3
1e4 kg is 1e7 g
so
d = m/V = 1e7/2e6 = 5 g/cm3
Therefore, the density of the ore sample is 5 g/cm3.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
2 m3 is 2e6 cm3
1e4 kg is 1e7 g
so
d = m/V = 1e7/2e6 = 5 g/cm3
Therefore, the density of the ore sample is 5 g/cm3.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Answer:
Density = 5 g/cm³
Step-by-step explanation:
We have density, ρ is the ratio of mass m and volume, V.
That is
[tex]\rho =\frac{m}{V}[/tex]
Mass, m= 1 x 10⁴ kg
Volume, V = 2 m³
Substituting in expression of density,
[tex]\rho =\frac{m}{V}=\frac{1\times 10^4}{2}=5000kg/m^3\\\\\rho=\frac{5000\times 10^3g}{10^6cm^3}=5g/cm^3[/tex]
Density = 5 g/cm³