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Given the system of constraints, name all vertices of the feasible region. Then find the maximum value of the given objective function.
x>0
y>0
y<1/3x+3
5>y+x
Objective Function: C = 6x _ 4y

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Below is the solution:

vertices: (0,3)(1.5, 3.5)(5,0) 
xy(0,3)= 0,3;6x – 4y= -12 
xy(1.5, 3.5)= 1.5,3.5;6x – 4y= -5 
xy(5,0)= 5,0;6x – 4y= 30 
maximum value = 30

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