Respuesta :

hello
I found the radius of the electron's orbit
but I couldn't get the correct energy at ground state using the electric potential energy formulas
the radius I found matches the accepted value of Bohr's hydrogen atom radius

Edit:

I found the energy, my calculator wasn't calculating the small numbers correctly, so I kept on getting zero.

the energy at ground state is 4.36*10^-18 J
I can't reupload a new picture of the solution. so if it's possible, you might want to repost your question and message me to answer it again.

btw the potential energy is:

((e^4)*m)/(4(Elipson0)*h^2)= 4.36*10^-18 J
Ver imagen OMAX
Use the formula in ev (13.6eV*Z^2)(n^2)

hydrogen Z = 1
ground state, so n=1

Ans: 13.6 ev
Q&A Education