Respuesta :
hello
I found the radius of the electron's orbit
but I couldn't get the correct energy at ground state using the electric potential energy formulas
the radius I found matches the accepted value of Bohr's hydrogen atom radius
Edit:
I found the energy, my calculator wasn't calculating the small numbers correctly, so I kept on getting zero.
the energy at ground state is 4.36*10^-18 J
I can't reupload a new picture of the solution. so if it's possible, you might want to repost your question and message me to answer it again.
btw the potential energy is:
((e^4)*m)/(4(Elipson0)*h^2)= 4.36*10^-18 J
I found the radius of the electron's orbit
but I couldn't get the correct energy at ground state using the electric potential energy formulas
the radius I found matches the accepted value of Bohr's hydrogen atom radius
Edit:
I found the energy, my calculator wasn't calculating the small numbers correctly, so I kept on getting zero.
the energy at ground state is 4.36*10^-18 J
I can't reupload a new picture of the solution. so if it's possible, you might want to repost your question and message me to answer it again.
btw the potential energy is:
((e^4)*m)/(4(Elipson0)*h^2)= 4.36*10^-18 J
Use the formula in ev (13.6eV*Z^2)(n^2)
hydrogen Z = 1
ground state, so n=1
Ans: 13.6 ev
hydrogen Z = 1
ground state, so n=1
Ans: 13.6 ev