Respuesta :
Mass of the system is 25.2 kg
Calculation:
F=ma
m = F/a where a = m/t^2
a=2.3/(1.3)^2 = 1.36 m/s^2
m=34.3/1.36
m=25.2 Kg
Calculation:
F=ma
m = F/a where a = m/t^2
a=2.3/(1.3)^2 = 1.36 m/s^2
m=34.3/1.36
m=25.2 Kg
Answer:
m = 12.6 kg
Explanation:
As we know that it covers total distance of 2.3 m in 1.3 s
so we will have
[tex]v_i = 0[/tex]
[tex]d = 2.3 m[/tex]
[tex]t = 1.3 s[/tex]
now we can use kinematics to find the acceleration
[tex] d = v_i t + \frac{1}{2}at^2[/tex]
[tex]2.3 = \frac{1}{2}a(1.3^2)[/tex]
[tex]a = 2.72 m/s^2[/tex]
Now we can use Newton's law
[tex]F = ma[/tex]
[tex]34.3 = m(2.72)[/tex]
[tex]m = 12.6 kg[/tex]