Answer:
The correct answer is - 733.69 mg.
Explanation:
given:
The volume of ascorbic acid = 50 ml
The volume of NaOH = 20.74 ml
Molarity of NaOH = 0.201 M
formula = C6H8O6
Solution:
moles of NaOH for titration = molarity of NaOH × The volume of NaOH
= 0.201 × 20.74 × 10^-3
=4.16874 × 10^-3
then molecular weight of ascorbic acid
= 6 × 12+ 8×1+ 6× 16
=176g/mol
the molecular mass would be
= 4.16874 × 10^-3 × 176
= 733.69 × 10^-3 g
=733.69 mg
