Assuming that I can have this quadratic equation equals y, here is what you might be looking for.
[tex]7x^{2} -6x+5=y[/tex]
insert the values of the point
[tex]7(1)^{2} -6(1)+5=6[/tex]
[tex]7^{2} -6+5=6[/tex]
[tex]49-6+5=6[/tex]
[tex]43+5=6[/tex]
[tex]48\neq 6[/tex]
Assuming that I can use y, Then no, this point would not satisfy this parabola.
Hope this helps.
