Hi there!
[tex]\large\boxed{\text{vf }\approx 29.70 m/s}[/tex]
Use the following kinematic equation to evaluate the final velocity:
vf² + vi² + 2ad, where:
vf = final velocity
vi = initial velocity
a = acceleration (due to gravity in this situation, or 9.8 m/s²)
d = distance
Plug in the given values. Note that vi = 0 m/s since the object was dropped from rest:
vf² = 0 + 2(9.8)(45)
Simplify:
vf² = 882
Take the square root of both sides:
√vf² = √882
vf ≈ 29.70
