Respuesta :

victorcarlos346

Answer:

[tex](x-3)^{2} +(y+2)^{2} =5^{2}[/tex]

Step-by-step explanation:

The equation of the circle with center A=(a,b) and radius = r are:

[tex](x-a)^{2}+(y-b)^{2} =r^{2}[/tex]

When A=(3,-2) and radius=r=-5

[tex](x-3)^{2} +(y+2)^{2} =5^{2}[/tex]

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