The water line from the street to my house is 1 inch diameter and made of PVC (i.e. smooth). The line is roughly 450 ft long. The water pressure in the line at the street is 130 psig. If I flow 10 gpm through the pipe, what pressure would I expect when I get to my house. My house is 10 ft higher in elevation than the water line at the street

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Cricetus Cricetus · Answer 1 · 2021-04-03T17:54:21+02:00

Answer:

The right solution is "126 Psi".

Explanation:

The given values are:

P₁ = 130 psig

i.e.,

= [tex]130\times 6.894[/tex]

= [tex]896.22 \ Kpa[/tex]

or,

= [tex]896.22\times 10^3 \ Pa[/tex]

Z₂ = 10ft

= 3.05 m

[tex]\delta[/tex] = 1000 kg/m³

According to the question,

Z₁ = 0

V₁ = V₂

As we know,

⇒ [tex]\frac{P_1}{\delta_g} +\frac{V_1^2}{2g} +Z_1=\frac{P_2}{\delta_g} +\frac{V_2^2}{2g} +Z_2[/tex]

On substituting the values, we get

⇒ [tex]\frac{P_1}{\delta_g} +0+0=\frac{P_2}{\delta_g} +0+Z_2[/tex]

⇒ [tex]\frac{896.22\times 10^3}{1000\times 9.8} =\frac{P_2}{1000\times 9.8} +3.05[/tex]

⇒ [tex]P_2=866330 \ P_a[/tex]

i.e.,

⇒ [tex]=866330\times 0.000145[/tex]

⇒ [tex]=126 \ Psi[/tex]