Answer:
y = -5/2x + 20/3
Step-by-step explanation:
x-int of 3x + 6y = 8
sub 0 for y
3x + 6(0) = 8
3x = 8
x = 8/3 or 2.667
line perpendicular to 2x - 5y = 10
put into y = mx + b form
2x - 5y - 10 = 0
5y = 2x - 10
y = 2/5 x - 2
find negative reciprocal of the slope 2/5 x (for the perpendicular line)
-5/2 x
find the y-int (b)
m = -5/2 x
must pass through (8/3,0)
y = mx + b
0 = -5/2(8/3) + b
0 = -40/6 + b
b = 20/3
therefor the equation of the line is y = -5/2x + 20/3
