Answer:
See explanations below
Step-by-step explanation:
What the step for answer
Given the nth terms of as sequence expressed as
Sins a ≥ 3, we can find the third term of the sequence
an = 2an-1 + an-2 - 2an-3
If a1 = 6 and a2 = 0 and a0 = 3
a3 = 2a2 + a1 - 2a0
a3 = 2(0) + 6 - 2(3)
a3 = 0 + 6 - 6
a3 = 0
If n = 4
a4 = 2a3 + a2 - 2a1
a4 = 2(0) + 0 - 2(6)
a4 = 0 + 0 - 12
a4 = -12
