Answer:
406850000 J
Explanation:
From the question
Q = cm...................... Equation 1
Where Q = Amount of heat, c = latent heat of water, m = mass of water
Given: c = 813700 J/g, m = 500 grams
Substitute these values into equation 1
Q = 500×813700
Q = 406850000 J
Hence the amount of heat requires to boil water at 100°C = 406850000 J
