Answer:
 m = 4.0
Explanation:
For this exercise in geometric optics we will use the equation of the constructor
     [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
where f is the focal length, p and q are the distance to the object and image, respectively.
In the exercise indicate the focal length f = 2.00 cm, the distance to the object p = 1.60 cm, let's find the distance to the image
     [tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p}[/tex]
    Â
let's calculate
     [tex]\frac{1}{q} = \frac{1}{2} - \frac{1}{1.6}[/tex]1 / q = ½ - 1 / 1.6
     [tex]\frac{1}{q}[/tex] = -0.125
     q = -8 cm
the magnification is
    m = - q / p
    m = 8/2
    m = 4.0
