Someone help! Again I'll give brainlist if right!
Step-by-step explanation:
Use TOA. (tan angle = opposite/adjacent)
Given angle A = 58
adjacent = 6 mi
[tex] \tan(a) = \frac{opposite}{adjacent} \\ \tan(58) = \frac{bc}{6} \\ bc = 6 \tan(58) \\ = 9.6mi(nearest \: tenth)[/tex]