Answer:
Attractive force and r = 0.399 m
Explanation:
One charge is positive and the other charge is negative. Opposite charges attract, so there has to be a force that attracts between them.
q1 = 10.0 x 10^-6 C
q2 = -3 x 10^-6 C
F = 1.7 N
Plug those values into Coulomb's Law:
[tex]F = k\frac{q1q2}{r^{2} } \\1.7 = \frac{(9x10^{9})(10.0 x 10^{-6})(-3 x 10^{-6})}{r^{2} }[/tex]
Solve for r
r = 0.399 m
