Answer: The new pressure is 3 psi.
Explanation:
Given: [tex]P_{1}[/tex] = 12 psi, [tex]T_{1} = 20^{o}C[/tex]
[tex]P_{2}[/tex] = ?, [tex]T_{2} = 5^{o}C[/tex]
Formula used is as follows.
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{12 psi}{20^{o}C} = \frac{P_{2}}{5^{o}C}\\P_{2} = \frac{12 psi \times 5^{o}C}{20^{o}C}\\= 3 psi[/tex]
Thus, we can conclude that the new pressure is 3 psi.
