Answer:
96.92 K
Explanation:
Applying,
V/T = V'/T'..................... Equation 1
Where V = Initial Volume, T = Initial Temperature, V' = Final Volume, T' = Final Temperature.
Make T the subject of the equation
T = VT'/V'................. Equation 2
From the question,
Given: V = 268 mL, V' = 824 mL, T' = 25°C = (25+273) = 298 K
Substitute these values into equation 2
T = (268×298)/824
T = 96.92 K
Hence the Initial temperature of Nitrogen gas is 96.92 K
