Answer:
[tex] \approx 31.63 \: {ft}^{2} [/tex]
Step-by-step explanation:
Area of the figure = 2 times the area of one semicircle with radius (5/2 = 2.5) 2.5 ft + Area of triangle with base 6 ft and height 4 ft.
[tex] = 2 \times \frac{1}{2} \pi {r}^{2} + \frac{1}{2} bh \\ \\ = 3.14 \times {(2.5)}^{2} + \frac{1}{2} \times 6 \times 4 \\ \\ = 3.14 \times 6.25 + 3 \times 4 \\ \\ = 19.625 + 12 \\ \\ = 31.625 \\ \\ \approx 31.63 \: {ft}^{2} [/tex]
