[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Area of circle is ~
[tex]\qquad \tt \dashrightarrow \: \pi {r}^{2} [/tex]
[tex]\qquad \tt \dashrightarrow \: \pi \cdot ( 8){}^{2} [/tex]
[tex]\qquad \tt \dashrightarrow \:64 \pi \: \: in {}^{2} [/tex]
So, option D is correct ~
