Lily begins solving the equation 4(x β 1) β x = 3(x + 5) β 11. Her work is shown below.
4(x β 1) β x = 3(x + 5) β 11
4x β 4 β x = 3x + 15 β 11
3x β 4 = 3x + 4
How can her partial solution be interpreted?
The equation has one solution: x = 0.
The equation has one solution: x = 8.
The equation has no solution.
The equation has infinite solut