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If the effort distance = 8 meters and the resistance distance = 1/2 meter. How much force does this man have to apply to lift the 1 ton (2000 N) weight?

Respuesta :

Answer:

Explanation:

Effort x effort distance = load x resistance  distance

effort distance = 8 m ,

load = 2000N

resistance distance = 1/2 m = 0.5 m

Putting the values in the equation above

effort x 8m = 2000N x .5

effort = 2000 x 0.5 / 8

= 125 N

force required = 125 N .

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