Answer:
[tex]{\small{\mathcal{\underline{\underline{\blue{ here \: is \: your \: solution...}}}}}} \\ \\ \small\mathfrak\purple{ \sin( \alpha = \: perpendicular \div hypotenuse \: ) } \\ \\ \small\mathfrak\purple{ = \: perpendicular = 20 ) } \\ \\ \small\mathfrak\purple{ \: hypotenuse = 29 \: ) } \\ \\ \small\mathfrak\purple{ \sin( \alpha = 20 \div 29}) \\ \\ {\small{\mathcal{\underline{\underline{\red{ hope \: it \: helps...}}}}}}[/tex]
