Answer:
22.54 moles of NaBr are needed
Explanation:
The reaction of Cl2 with NaBr occurs as follows:
Cl2 + 2NaBr → 2NaCl + Br2
Where 1 mole of Cl2 requires 2 moles of NaBr for a complete reaction
As in the problem, we have 11.27 moles of Cl2, the moles of NaBr required are:
11.27mol Cl2 * (2mol NaBr / 1mol Br2) =
22.54 moles of NaBr are needed
