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The Atlanta Journal Constitution conducted a survey of 900 registered voters to determine which voting method they prefer. The AJC found 60% favored voting on paper ballots they filled themselves (as opposed to voting with a computer). Find a confidence interval for the proportion of all registered voters that favor at 85% confidence level. a) (0.576, 0.624) b) (0.376, 0.424) c) (0.583, 0.617) d) (0.586, 0.614)

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Answer:

a) (0.576, 0.624)

Step-by-step explanation:

Given that the sample proportion (p) = 60% = 0.6, sample size (n) = 900, confidence (C) = 85%

α = 1 - C = 1 - 0.85 = 0.15

α/2 = 0.075

The z score of α/2 (0.075) corresponds with the z score of 0.425 (0.5 - 0.075) which is equals to 1.44, hence [tex]z_\frac{\alpha }{2} =1.44[/tex]

The margin of error (E) is:

[tex]E=z_\frac{\alpha }{2} *\sqrt{\frac{p(1-p)}{n} } =1.44*\sqrt{\frac{0.6(1-0.6)}{900} } = 0.024[/tex]

The confidence interval = p ± E = 0.6 ± 0.024 = (0.576, 0.624)

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