papaleta009 papaleta009

03-06-2021
Mathematics

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irisalvillar35 irisalvillar35

03-06-2021

Answer:

1st - 10(n-4)

2nd - 3n^3 x (2n ^3 - 4n^2 -5)

3rd - (k^2-3) x (k^2 +3)

4th 3(x-2)x(x+2)

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