Answer:
I am pretty sure it's 495
Step-by-step explanation:
The context of this problem makes me think that the order in which the sites are in does not matter
if that's the case we can solve this using combinations
the combinations formula is as follows:
ACB= [tex]\frac{A!}{(A-B)!*B!}[/tex]
so 12C4= [tex]\frac{12!}{(12-4)!*4!}=495[/tex]
