Answer:
x = [tex]\sqrt{119\\}[/tex]
Step-by-step explanation:
formula for this is [tex]\sqrt{a^{2}-(b/2)^{2}}[/tex] where a is the altitude and b is the base
altitude = 12
base = 10
[tex]\sqrt{12^{2}-(10/2)^{2} }[/tex]
[tex]\sqrt{144-5^{2} }[/tex]
[tex]\sqrt{144-25}[/tex]
[tex]\sqrt{119}[/tex] ≈ 10.9
so I would say x = [tex]\sqrt{119}[/tex] or 10.9, but seeing as thats not an option, then I'm not sure
