Answer:
0.31 μm
Explanation:
this question wants us to Determine the depletion region width, xn, in the n-side in unit of μm. using the information below.
density in the p-side = 5.68x10^16
density in the n-side = 1.42x10^16
[tex]\sqrt{\frac{2*12.7*8.85E-10}{1.6E-14}(\frac{1}{5.68E16}+\frac{1}{1.42E16} )(1.2) }[/tex]
= √(1.42x10⁵)(1.76056335x10⁻¹⁷ + 7.042253521x10⁻¹⁷)(1.2)
= √150.74x10⁻¹¹
= 3.882x10⁻⁵
approximately 0.39μm
xn = 0.39 x 0.8
= 0.31μm
0.31 um is the depletion region width. thank you!
