Answer:
Step-by-step explanation:
(-6 , 1) & (8 , 1)
d1 = 8 + I - 6I = 8 + 6 = 14
(1,6) & (1 , -4)
d2 = 6 + I -4 I = 6 + 4 = 10
Area of rhombus = [tex]\frac{d_{1}*d_{2}}{2}[/tex] where d1 & d2 are the diagonals
[tex]\frac{14*10}{2} = 7 * 10 = 70 \ square \ units[/tex]
