To find the quotient [tex]\dfrac{14x^3 -21x^2 + 28x}{7x}[/tex], you can break this into three separate fractions, each over [tex]7x[/tex]:
[tex]\dfrac{14x^3 -21x^2 + 28x}{7x} =~ \dfrac{14x^3}{7x} ~-~\dfrac{ 21x^2}{7x} ~+~\dfrac{28x}{7x}[/tex]
Now you need to just divide the 7 into each coefficient in the numerator and then cancel out x's as appropriate.
