Respuesta :

caylus

Answer:

Step-by-step explanation:

The foci:

F=(1,0)

F'=(-1,0)

The co-vertices:

V=(0,2

V'=(-2,0)

[tex]\dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1\\\\with\ \\b=2\\and \\2*a=2*|FV|=2*\sqrt{5} \, a=\sqrt{5}\\\\\dfrac{x^2}{5} +\dfrac{y^2}{4} =1\\[/tex]

Otras preguntas

Q&A Education