Answer:
Time to reach maximum height can be obtained from v=u+at
0=20+(−10)t
t=2s
s=ut+0.5at
2
=20(2)+0.5(−10)(2)
2
=20m
Thus, total distance for maximum height is 45 m
s=ut+0.5at
2
45=0+0.5(10)(t ′ )
2
t
′
=3s
Total time= 3+2= 5s
Explanation:
TAKE 22.0 IN PLACE OF 20 U WILL GET YR ANSWER
HOPE IT HELPS
